- #1

Lengalicious

- 163

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Question: Find the general solution to the following differential equation:

Equation: y'(x) = sec

^{2}(3x + 1)

My answer: Don't I just integrate? So dy/dx = sec

^{2}(3x + 1)

then, y = sec

^{2}(3x + 1) dx

so y = (tan(3x+1))/3