Check my answer please simple current/power problem

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Homework Help Overview

The discussion revolves around a problem involving the charging of an electric vehicle, specifically the Nissan Leaf, which has a battery pack and requires calculations related to current and cost for charging. The subject area includes electrical power, current, and energy calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between power, voltage, and current in the context of charging the Nissan Leaf's battery. There are attempts to calculate the current required for charging and the cost associated with it. Questions arise regarding the correctness of initial calculations and the implications of charging time on current.

Discussion Status

Several participants express disagreement with the original poster's calculations, suggesting that the current values provided are unrealistic. There is a focus on clarifying the units involved in the calculations and the correct application of formulas related to energy and power. Some participants provide alternative calculations and emphasize the need to reconsider the assumptions made.

Contextual Notes

Participants note that the problem involves converting between different units of energy and power, and there is a discussion about the practical limitations of charging current based on typical household electrical systems.

nchin
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The Nissan leaf is powered by 107 hp electric motor, kept alive by a pack of batteries, It takes 79.85 kilowatts to run the motor, assuming 100% efficiency.

a) The Nissan contains a 24kWh battery pack and its estimated that using a 220V charging dock at home. The leaf can be charged in 8 hours. What the current as the leaf is charging?
b) if it cost 11 cents perkilowatthour, how much does it cost to fully charge the leaf?

my answers:
a) i = P/V =>(24000*8)/220 = 872.7 A
b)79.851 x 8 hours = 638.808
638.808 x .11 = $70.26


is this right?
 
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Not right.

If the battery can supply 24 kW for 1 hr then if it had to be recharged in 1 hr it would take how many amperes to recharge? And if we can take 8 hrs to recharge, would that take more or less current?
 
rude man said:
Not right.

If the battery can supply 24 kW for 1 hr then if it had to be recharged in 1 hr it would take how many amperes to recharge? And if we can take 8 hrs to recharge, would that take more or less current?

i don't understand. (24 kW times 8 hours to recharge)/220V?
 
Think about the units for kWh

= Watts * time(in hours)/1000
= Current(Amp) * Voltage(volts) * time(in hours)/1000

PS I believe a Leaf can be charged from a normal domestic socket so 800-900A is unlikely
 
CWatters said:
Think about the units for kWh

= Watts * time(in hours)/1000
= Current(Amp) * Voltage(volts) * time(in hours)/1000

PS I believe a Leaf can be charged from a normal domestic socket so 800-900A is unlikely

24000 * 8 hours /1000 = 192 W

current=192W / 220Volts = 0.87 amps?
 
nchin said:
24000 * 8 hours /1000 = 192 W

current=192W / 220Volts = 0.87 amps?

No you missunderstood my post totally.

I start from the beginning ...

The battery stores a quantity of energy. I wish they would specify that in Joules but they used kWH instead which is ok.

kWH means kilo Watt Hours so a sum that gives an answer in kWH will involve multipling power(in Watts) by time(in hours).

Specifically...

Energy (in KWH) = Power(in Watts) * time(in hours)/1000.....(1)

but as you know

Power(in watts) = Current(in Amps) * Voltage(Volts)......(2)

substitute to give..

Energy (in KWH) = Current(Amp) * Voltage(volts) * time(in hours)/1000

The question asks for the current so rearrange that to give

Current = (Energy * 1000) / (Voltage * time)

Then plug the numbers in.
 
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