Checking if f(x)=g(x)+h(x) is onto

Click For Summary

Discussion Overview

The discussion revolves around the conditions under which the function f(x) = g(x) + h(x) is onto, particularly focusing on the continuity of h(x) and the properties of g(x) when it is a polynomial of odd degree. Participants explore the implications of these properties on the overall function.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions why h(x) must be continuous, noting that while polynomials are continuous, there are examples of functions that combine continuous and discontinuous elements.
  • Another participant clarifies that while discontinuous functions can exist, they do not apply in the general case for the function being discussed.
  • There is a suggestion that h(x) must be continuous for f(x) to be onto, although this is not universally accepted.
  • Participants discuss the implications of g(x) being a polynomial of odd degree, indicating that its range is (-∞, ∞).
  • Concerns are raised about the definition of a bounded function, with clarification that it refers to the values of the function rather than its domain.
  • One participant prompts a consideration of the limits of a polynomial of odd degree at positive and negative infinity, questioning whether these limits can be equal.
  • A participant asserts that the limits will not be equal, while another confirms that this leads to the conclusion that the polynomial is onto.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of h(x) being continuous and the implications of g(x) being a polynomial of odd degree. The discussion remains unresolved regarding the general case of f(x) being onto.

Contextual Notes

There are limitations regarding the assumptions about the continuity of h(x) and the definitions of bounded functions, which are not fully resolved in the discussion.

Titan97
Gold Member
Messages
450
Reaction score
18
This is picture taken from my textbook.
WP_20150809_12_11_28_Pro.jpg

I understood the last two statements "To check whether..". A function is one if its strictly increasing or decreasing. But I am not able to understand the first statement. Polynomials are continuous functions. Also, a continuous function ± discontinuous function may be continuous. (eg: {x}+[x]) So why should h(x) necessarily be a continuous function?
 
Mathematics news on Phys.org
It does not make any statement for discontinuous functions. Sure, there are discontinuous h(x) that would still work, but not in the general case.

Unrelated:
The sum of a continuous function and a discontinuous function is discontinuous. Your example sums two discontinuous functions.
 
  • Like
Likes   Reactions: Titan97
So h(x) has to be continuous. (I got cinfused while typing). But what makes f(x) onto?
 
What do you know if g(x) is a polynomial of odd degree?
Does the information about continuity and bounds change if you add a bound continuous function?
 
For polynomials of odd degree, the range is (-∞,∞). If h(x) is only defined ∀ x∈[a,b], then f(x)=g(x)+h(x) is only defined ∀ x∈(a,b).
 
That's not how "bounded function" is meant here. Its function values are limited, not its domain.
 
  • Like
Likes   Reactions: Titan97
The continuity won't change if you add such a function like x+sinx
 
Given a polynomial of odd degree ##P(x)##. Think about
[tex]\lim_{x\rightarrow +\infty} P(x)~\text{and}~\lim_{x\rightarrow -\infty} P(x)[/tex]
Can those be equal? Can you give an example when those limits will be equal?
 
  • Like
Likes   Reactions: Titan97
They won't be equal
 
  • #10
So what will they be concretely? Can you deduce from that that the function ##P(x)## is onto?
 
  • Like
Likes   Reactions: Titan97
  • #11
Yes.
 
  • #12
OK, then the general case shouldn't be too difficult either.
 
  • Like
Likes   Reactions: Titan97

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
22
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K