Checking if Three Operators Form a 3-Vector with SO(3) Commutation Relations

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jfy4
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Hello,

Lets say I have three operators

[tex]k_3=\partial_\phi[/tex], [tex]k_1=\sin\phi\partial_\theta+\cot\theta\cos\phi\partial_\phi[/tex], [tex]k_2=\cos\phi\partial_\theta-\cot\theta\sin\phi\partial_\phi[/tex].

These operators satisfy the SO(3) commutation relations:

[tex][k_i,k_j]=\epsilon_{ijk}k_k[/tex]

How can I check to see if these three operators together form a 3-vector?
 
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In general you prove a set of operators Vi form a vector by showing how they transform under rotations, namely [Li, Vj] = eijk Vk. But in this case, your operators Vi already are Li!

I think what I'd do is to start out by defining Li in Cartesian coordinates, Lz = x∂y - y∂x, etc, transform them to spherical coordinates and show they reduce to your Vi. That substantially proves it.
 
Bill_K said:
In general you prove a set of operators Vi form a vector by showing how they transform under rotations, namely [Li, Vj] = eijk Vk. But in this case, your operators Vi already are Li!

I think what I'd do is to start out by defining Li in Cartesian coordinates, Lz = x∂y - y∂x, etc, transform them to spherical coordinates and show they reduce to your Vi. That substantially proves it.

Ok, I have managed to show that they come from the Cartesian coordinates, however, It still does not seem to me that these 3 operators are specifically assigned to anyone component of a vector. That is,

[tex]L_x=z\partial_y-y\partial_z[/tex]

but after the transformation

[tex]L_x=\sin\phi\partial_\theta+\cot\theta\cos\phi\partial_\phi[/tex]

What component would this correspond to in [tex](r,\theta,\phi)[/tex] coordinates? How can I determine what component these three operators correspond too?