1. The problem statement, all variables and given/known data "Calculate the grams of acetic acid per liter of vinegar" 2. Relevant equations Previous problem stated the multiply the average molarity of diluted vinegar times 10= 2.7 M Vinegar (acetic acid)= H(C2H3O2) molecular weight= 60.06 g 3. The attempt at a solution moles= M x L 2.7M x 1L = 2.7 moles 2.7 moles x 60.06 g= 162.16 g This seems way too high. and i wasn't given anything really and it is driving me insane!! Thank you in advance for anyone who helps!