Chemical Reactions: Stronger Bonds, Reactive Elements

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Discussion Overview

The discussion revolves around the nature of chemical bonding, particularly focusing on the reactivity of elements and the stability of compounds formed, such as water (H2O) and hydroxide (OH-). Participants explore concepts related to bond strength, stability, and the behavior of reactive elements in chemical reactions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests that more reactive elements form stronger bonds, questioning why bonding continues after initial reactions when elements are already in a stable state.
  • Another participant clarifies that hydroxide (OH-) has a negative charge and can react with hydrogen ions (H+) to form stable water (H2O) or hydronium (H3O+), introducing the concept of equilibrium in water reactions.
  • It is noted that HO is not stable, and the stable form is H2O, with hydrogen being monovalent and oxygen being divalent, leading to further bonding possibilities.
  • One participant expresses a need for systematic chemistry education, suggesting resources for learning.
  • Another participant mentions Linus Pauling as a notable chemist, responding to a query about respected authors in the field.
  • Further clarification is provided on the behavior of hydroxide ions in relation to hydrogen ions, describing how water acts as a buffer system that can adjust to changes in ion concentration.
  • A participant explains that oxygen, needing two electrons to achieve stability, readily bonds with two hydrogen atoms, which is described as oxidation.

Areas of Agreement / Disagreement

Participants express differing views on the stability of hydroxide versus water and the implications of reactivity in bonding. The discussion contains multiple competing perspectives and remains unresolved on several points.

Contextual Notes

Limitations include assumptions about the definitions of stability and reactivity, as well as the complexity of equilibrium reactions that are not fully explored in the discussion.

LogicalAcid
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The more reactive an element, the stronger bonds it forms, because the same energy must be put into that bond to separate them that was put out due to the reaction. Most of the elements we are made of, in pure form, are reactive correct? Carbon and oxygen have very high electronegativities, and Hydrogen is reactive as well. Therefore, shouldn't elements stop bonding after one or two reactions? For instance, let's make some HO. After the reaction is done, I am sure much energy was put into the reaction,due to both the elements being very reactive. So why is it that when another Hydrogen atom comes along, the HO will react with the lone H atom, if they are already in a stable state?
 
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Firstly it's OH^{1-}, meaning it has a negative charge so when a hydrogen ion H^+ (a proton) comes along it is attracted and creates a stable and neutral water molecule H_2O but it can also create a monoprotic hydronium H_3O^+. There is a constant equilibrium reaction in water H_2O + H^+ \leftrightarrow H_3O^+ meaning it changes back and forth because water acts as a base and an acid.
 
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Obviously HO is not stable, it is H2O that is stable. In the simplest version - hydrogen is monovalent, oxygen is divalent. In OH hydrogen is happy (bonded), but oxygen has one valence left, so it still wants to bond with something. Another hydrogen will do.

I think instead of asking random questions you should start with some systematic chemistry course. For example you may try http://preparatorychemistry.com (I must admit I don't know the book, but I have heard good opinions).
 
Kevin_Axion said:
Firstly it's OH^{1-}, meaning it has a negative charge

Hard to say what it is, it can be as well OH. (free radical).
 
Borek said:
Obviously HO is not stable, it is H2O that is stable. In the simplest version - hydrogen is monovalent, oxygen is divalent. In OH hydrogen is happy (bonded), but oxygen has one valence left, so it still wants to bond with something. Another hydrogen will do.

I think instead of asking random questions you should start with some systematic chemistry course. For example you may try http://preparatorychemistry.com (I must admit I don't know the book, but I have heard good opinions).

Thank you. And if I may ask, what are some dignified Chemists that are also authors?
 
No idea what you are asking about, but let's say Linus Pauling.
 
Kevin_Axion said:
Firstly it's OH^{1-}, meaning it has a negative charge so when a hydrogen ion H^+ (a proton) comes along it is attracted and creates a stable and neutral water molecule H_2O but it can also create a monoprotic hydronium H_3O^+. There is a constant equilibrium reaction in water H_2O + H^+ \leftrightarrow H_3O^+ meaning it changes back and forth because water acts as a base and an acid.

briefly the above states that :
water is a buffer system if ANY ions of any other element/compound are present
that means for example (caps means more, / means less)
standard: h+ + oh- -> h20
excess H+ : H+ + /oh- -> h20 ) due to there being more acid, the system automatically balances this addition of H+ by using some of the OH-, to creates more H20
the reverse would occur if more OH- was added.

(for chemists out there, I know that is not the buffer system equation, but it is a simple way to describe it )

Due to this, it literally depends on how many hydrogen ions are present in the environment of the OH- even if there is only one, one water molecule will form. think of it as : 'The oh- wants to be ph neutral, so it wants a H+ to become H20'
The only way to get OH- in a place where it could become water is for the OH- to be in excess.

I realize this is very very simple. but i think it may help
 
Oxygen is diatomic. It only needs to receive two electrons to be in a "stable" state like the noble gases, which have an outer electron shell of 8 - oxygen has 6. So when 2 hydrogen atoms come along, oxygen is quite happy to bond with these. This is called Oxidation.
 

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