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maylandchastity

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## Homework Statement

The equilibrium constant, Kp, for the following reaction is 0.636 at 600 K:

COCl2(g) CO(g) + Cl2(g)

Calculate the equilibrium partial pressures of all species when COCl2(g) is introduced into an evacuated flask at a pressure of 1.73 atm at 600 K.

## Homework Equations

Included below

## The Attempt at a Solution

The equilibrium constant, Kp, for the following reaction is 0.636 at 600 K:

COCl2(g) CO(g) + Cl2(g)

Calculate the equilibrium partial pressures of all species when COCl2(g) is introduced into an evacuated flask at a pressure of 1.73 atm at 600 K.

PCOCl2=

PCO=

PCl2=

setting up ICE, I know that Kp=x/(1.73-x)=.636

(.636)[1.73-x]^2=x

(.636)[1.73^2-2(1.73)x + x^2]=x

(.636)x^2-[2(1.73)(.636)+1]x + (.636)(1.73)^2

x^2-[2(1.73)+1/(.636)]x + 1.73^2= 0

a=1

b= -[2(1.73)+1/(.636)]= -5.032

c= (1.73)^2= 2.993

quadratic equation such that:

[(-5.032)^2-4(2.993)]^1/2 = [13.349]^1/2= 3.654

x=(-(-5.032)+-3.654)/2

x=4.343 or .689

Go with .689 since the other value of x is greater than the initial pressure of 1.73.

PCO=PCL2=(1.73-x)=(1.73-.689)=1.041

PCOCL2=x=.689