Chemistry/The equilibrium number/ I really

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SUMMARY

The discussion centers on the equilibrium of the reaction N2 (g) + 3H2 (g) <===> 2NH3 (g) with initial conditions of 2 moles of N2 and 4 moles of H2 in a 0.4 L container. At equilibrium, 1.14 moles of N2 remain, leading to the need to calculate the equilibrium number of moles of hydrogen (H2), the amount of ammonia (NH3) produced, and the equilibrium constant (Keq). The relationship between the changes in moles (x, y, z) is established through stoichiometry, specifically that z = 3x for the production of ammonia.

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  • Calculate the equilibrium number of moles of hydrogen (H2) using the ICE table method
  • Determine the amount of ammonia (NH3) produced (z) based on stoichiometric relationships
  • Compute the equilibrium constant (Keq) for the reaction
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1. N2 (g) + 3H2 (g) <===> 2NH3 (g)
initial 2mol ----- 4mol -------------- 0
change -x ------ -y ---------------- +z
End 1.14

2 mol N2 mixed with 4 mol H2 in 0.4 L container. At equilibrium 1.14 of N2 remain


There were 2 other questions too:

What is Y and what is X. I solved those but I can't do the rest, my answers are wrong

1) What is the equilibrium number of moles of hydrogen?

2) What is z, that is, how much ammonia is produce?

3) What is the equilibrium constant, Keq?



I tried to answer these questions over and over but it turns out wrong. I need hel soon, I'm stuck .please help
 
Last edited:
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I am not sure what the quastion is - were you given the ICE table, or have you made it on your own, assigning x, y and z to different reagents?

x, y and z are connected by stoichiometry of the reaction. For example - for every mole of N2 that reacted, 3 moles of NH3 are produced, thus z=3x.

--
methods
 

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