1. The problem statement, all variables and given/known data 2 squares are chosen at random from a chess board.What is the chance that these 2 squares will share exactly 1 corner? 2. Relevant equations P=favourable possibilities/Total possibilities 3. The attempt at a solution So,the total no of possibilities should be 64C2. Now,for favourable... For the 4 corners,only 1 square is possible,so 4 cases. For one side(excluding the corners) there can be 2 squares for every square we choose.,i.e 6×2=12 cases in on side...48 cases for all sides. Now,we are done with the borders and are just left with the middle ones. For each middle one there can be 4 possible squares..i.e, 36×4=144 cases Summing up,we get P=(4+48+144)/64C2 =196/64C2 Is this correct or have i missed (or added) something?