Cigarretes are expensive(compound interest problem)

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Homework Help Overview

The discussion revolves around a compound interest problem involving the monthly investment of money typically spent on cigarettes into a savings account with a specified interest rate. Participants are exploring how to accurately calculate the future value of these investments over a long period.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to derive a formula to account for multiple deposits and their compounding interest over time. There is discussion about the correct application of the compound interest formula and how to handle the changing principal amount with each deposit.

Discussion Status

Some participants have shared different formulas and approaches to calculate the future value of the investments. There is acknowledgment of confusion regarding the results obtained from various methods and calculators, indicating an ongoing exploration of the problem without a clear consensus on the correct approach.

Contextual Notes

Participants mention potential discrepancies in results from different formulas and online calculators, highlighting the complexity of the problem and the need for clarification on the correct application of compound interest principles.

Gablar16
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I've been circling his problem for a little while and cannot find how to approach it.

A typical smoker spends 55 dollars a month on cigarrettes. Suppose that the smokers invest at the end of the month that same amount in a savings account at 4.8% compounded monthly. How much money will be in the account at the end of 40 years?


I translated that from spanish so it might be a little unclear, polease don't hesitate to ask for clarifycation.

I know that the compound interest formula is A= P(1+(r/n)^nt but the problem is that everytime I make a deposit I have to add last month amount with interest plus this months amount and it keeps mounting every month. I think the problem lies in P. I Tried plugging in all the numbers and if I invest only the first 55 dollars I will have 2305.60 at the end of the 40 years but I know that's wrong, as the real amount should be much higher. Any push in the right direction would me appreciated greatly. Thanks
 
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I just scratched this out on paper, and I am trying to get a general solution for this: F = [1+(i/n)^nt]*A + [1+(i/n)^nt-1]*A + [1+(i/n)^nt-2]*A + ...
so its like calculating n different accounts, each with the same principle investment, just with one less compounding term for each successive account
 
Shouldn't A change over time too?

btw thanks for the reply
 
Thanks for the link Ronnin it really helped a lot.

I found a different formula in here
http://mathforum.org/dr.math/faq/faq.interest.html"

but they both gave me the same result.
The website you gave me used (a - ar^(n+1))/(1-r) where;

a=deposit (55)
r=the rate (1+(.048\12))
n=479 (from the geometric sequence?)

I then substituted and

(55-55(1.004)^480)\(-.004)=79679.7


The other formula P = M([1+(i/q)]^nq-1)(q/i) where;

M= 55
i= .048
q=12
n=40

gave me the same result.

My only confusion is that I tried to verify with a web calculator http://www.dinkytown.net/java/CompoundSavings.html" , but it gave a number that it is a bit higher, can someone verify for me? Thanks again
 
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