1. The problem statement, all variables and given/known data http://img87.imageshack.us/img87/6702/yffigure2534pk3.jpg [Broken] The circuit in the above figure contains two batterires, each with an emf and an internal resistance, and two resistors. Find a) the current in the circuit (magniturde and direction) b) the terminal voltage Vab of the 16V battery c) the potential difference Aac of paoint a with respect to point c 2. Relevant equations I = V/R V = [tex]\epsilon[/tex] - Ir Vac = Vab-Vbc 3. The attempt at a solution I1 = V/R = 16V/1.6ohms = 10A (first battery) I2 = V/R = 8V/1.4ohms = 5.7A (2nd battery) Vbc = [tex]\epsilon[/tex] - IR = (16+8V) - (10A + 5.7A)(9ohms) = -117.3V Vab = [tex]\epsilon[/tex] - IR = (16V) - (10A)(1.6ohms) = 0V Vac = Vab-Vbc = 0 - (-117.3V) = 117.3V I'm not quite sure if I did the problem correctly, if anyone could check my method I would greatly appreciate it.