Circuits (Nodal and loop anal. finding current through branch)

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SUMMARY

The discussion centers on calculating the short-circuit current (isc) in a circuit analysis problem. The correct value for isc is established as 6mA, while the user initially calculated it as 0mA. The equations used by the user are questioned, specifically the relationships between currents i1, i2, and Ix. The analysis suggests that Ix equals i2 and that the equation 2Ix = i2 - i1 is relevant for solving the problem.

PREREQUISITES
  • Understanding of nodal and loop analysis in electrical circuits
  • Familiarity with current relationships in circuit theory
  • Basic knowledge of Ohm's Law and Kirchhoff's laws
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Study the principles of nodal analysis in electrical engineering
  • Learn how to apply Kirchhoff's Current Law (KCL) in circuit problems
  • Explore techniques for solving simultaneous equations in circuit analysis
  • Review examples of calculating short-circuit currents in various circuit configurations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing electrical circuits for accurate current calculations.

Miike012
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I am trying to solve for isc. The correct answer is isc = 6mA but I got 0 mA.

My equations must be correct... If they are not please someone explain why.

Thank you.
 

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Miike012 said:
I am trying to solve for isc. The correct answer is isc = 6mA but I got 0 mA.

My equations must be correct... If they are not please someone explain why.

Thank you.
That's a rather difficult image to read: sideways and illuminated through a partially open blind.
attachment.php?attachmentid=66029&d=1390766400.jpg


Your choices for i1 & i2 are not the most convenient.

It looks to me like:

Ix = i2 = isc

and

2Ix = i2 - i1 .
 

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