1. The diagram attached shows part of an electric circuit. What is the current through resistor R1? To summarize: I=6.0 A R1 = 11.0 Ω R2 = 33.0 Ω R3 = 67.0 Ω R2 and R3 are in parallel, and R1 and R2 and 3 are in parallel. I know we aren't supposed to attach pictures of questions, but a diagram does make my question a lot easier to understand. 2. Relevant equations V=IR IT in series = I1=I2=I3 IT in parallel = I1+I2+I3 RT in series = R1+R2+R3 RT in parallel = [(1/R1)+(1/R2)+(1/R3)]-1 3. The attempt at a solution Using the resistor laws, I can find resistance of R2 and 3 by (1/33+1/67)-1. Using Kirchoff's Laws, I know that the resistance coming out has to equal the 6.0 A. But I don't get how all this information is relevant. The question doesn't give me voltage or any other information and I don't know how to figure out how much current goes through each resistor.