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**1. The diagram attached shows part of an electric circuit. What is the current through resistor R**

_{1}?To summarize:

I=6.0 A

R

_{1}= 11.0 Ω

R

_{2}= 33.0 Ω

R

_{3}= 67.0 Ω

R

_{2}and R

_{3}are in parallel, and R

_{1}and R

_{2 and 3}are in parallel.

*I know we aren't supposed to attach pictures of questions, but a diagram does make my question a lot easier to understand.*

## Homework Equations

V=IR

I

_{T in series}= I

_{1}=I

_{2}=I

_{3}

I

_{T in parallel}= I

_{1}+I

_{2}+I

_{3}

R

_{T in series}= R

_{1}+R

_{2}+R

_{3}

R

_{T in parallel}= [(1/R

_{1})+(1/R

_{2})+(1/R

_{3})]

^{-1}

## The Attempt at a Solution

Using the resistor laws, I can find resistance of R

_{2 and 3}by (1/33+1/67)

^{-1}.

Using Kirchoff's Laws, I know that the resistance coming out has to equal the 6.0 A.

But I don't get how all this information is relevant. The question doesn't give me voltage or any other information and I don't know how to figure out how much current goes through each resistor.