Electric circuit problem, finding current through a resistor

2 replies · 2K views · last reply
physics604
Messages
92
Reaction score
2
1. The diagram attached shows part of an electric circuit. What is the current through resistor R1?

To summarize:
I=6.0 A
R1 = 11.0 Ω
R2 = 33.0 Ω
R3 = 67.0 Ω

R2 and R3 are in parallel, and R1 and R2 and 3 are in parallel.

I know we aren't supposed to attach pictures of questions, but a diagram does make my question a lot easier to understand.


Homework Equations



V=IR
IT in series = I1=I2=I3
IT in parallel = I1+I2+I3
RT in series = R1+R2+R3
RT in parallel = [(1/R1)+(1/R2)+(1/R3)]-1

The Attempt at a Solution



Using the resistor laws, I can find resistance of R2 and 3 by (1/33+1/67)-1.

Using Kirchoff's Laws, I know that the resistance coming out has to equal the 6.0 A.

But I don't get how all this information is relevant. The question doesn't give me voltage or any other information and I don't know how to figure out how much current goes through each resistor.
 
Attachments
  • Circuit schematic: a 6.0 A current enters from the left into a node, splitting into three parallel branches. Top branch R1 = 11.0 Ω; middle branch R2 = 33.0 Ω in parallel with R3 = 67.0 Ω in a lower branch, rejoining at the right node.
    diagram.PNG
    2.4 KB · Views: 554
Notice that ALL of the resistors are in parallel. Find the voltage across all of them, then find the current through each one.