Circuits with parallel resistors

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SUMMARY

The discussion focuses on calculating voltage and current in circuits with parallel resistors. In the first scenario, a circuit with a 10V battery and resistors R1=10ohm, R2=40ohm, and R3=50ohm confirms that the voltage across each resistor is 10V. In the second scenario, with resistors R1=10ohm, R2=20ohm, and R3=500ohm, the current through R2 is given as 100mA, leading to a calculated current of 200mA through R1, based on the voltage being the same across parallel resistors.

PREREQUISITES
  • Understanding of Ohm's Law
  • Knowledge of parallel resistor circuits
  • Ability to perform basic electrical calculations
  • Familiarity with voltage-current-resistance (V-I-R) relationships
NEXT STEPS
  • Study the principles of parallel circuits in electrical engineering
  • Learn how to calculate total resistance in parallel resistor configurations
  • Explore advanced circuit analysis techniques using Kirchhoff's laws
  • Investigate the impact of varying resistor values on current distribution
USEFUL FOR

Students studying electrical engineering, hobbyists building circuits, and anyone interested in understanding the behavior of parallel resistor configurations.

chiurox
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Homework Statement


1) A circuit contains a 10V battery and three resistors in parallel. The resistors have values R1=10ohm, R2=40ohm, R3=50ohm. What is the voltage across each resistor?

2)This time, the 3 resistors in parallel have values R1=10ohm, R2=20ohm, R3=500ohm. The current flowing through R2=100mA. What is the current flowing through R1?


Homework Equations





The Attempt at a Solution


1) 10 V across each, because the voltage is the same across parallel resistors right?

2) I made a V-I-R chart. Since R2 has a current of 100mA and its resistance is 20ohm, then the voltage is 2.0V. Since the resistors are in parallel, the voltage is the same for R1.
So 2volts=I(10ohm)
I=200 mA is this correct?
 
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Hi chiurox,

That looks correct to me.
 
yeah that's absolutely right
 
Oh... ok, I was a bit insecure. thanks
 

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