Circular Motion, an object attached by a string to a motor

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
7 replies · 2K views
SDTK
Messages
30
Reaction score
0

Homework Statement



A pendulum traveling at constant speed along a circular path
Determine the angle that the string makes with the vertical.

T[/B]he length of the string was measured to be 60 cm.
The period was measured to be 1.41 s
The frequency was found to be 0.709


2. Homework Equations

Is it possible to find the radius with only the Period T and frequency f?

3. The Attempt at a Solution

I believe that it should be possible to use the period and frequency to find the velocity, and from there the radius. Once I have the radius, I can find the angle.

Using:
v = 2(pi)r / T, v = 2 (pi)fr,
v = (2 x pi x radius)/period, v = 2 x pi x frequency x radius

a = v^2/r = (2(pi)f)^2r =(2(pi)/T)^2 r
a = velocity squared / radius = (2 x pi x frequency) squared x radius
= ((2 x pi) / T))squared x radius

I have tried solving for "r" and substituting the solution in order to find velocity, ... but I end up circling back the an equation with both the two unknown variables that I am trying to find, v and r.

with advanced thanks for any advise,
D.T.
 
Physics news on Phys.org
How about drawing a free body diagram of the pendulum? Identify all forces acting and apply Newton's 2nd law.
 
  • Like
Likes   Reactions: SDTK
Referring to the thread title, I'm not seeing where the motor comes in...
 
gneill said:
Referring to the thread title, I'm not seeing where the motor comes in...
I'm guessing the string of the pendulum is tied to some spinning axis--driven by the motor.
 
  • Like
Likes   Reactions: SDTK
Doc Al said:
I'm guessing the string of the pendulum is tied to some spinning axis--driven by the motor.
Ah. Alrighty then. :smile:
 
Air resistance is not considered
scan0002.jpg


I understand that that force (net) = ma = (mv^2)/r
and that mass "cancels out" so Force(net) = a = v^2 / r.

Velocity is not known. Neither is the radius, or angle

(the length of the string providing the tension, the period and the frequency are known.)

I thought that I could solve for velocity, and from velocity, solve for radius, ... but am now wondering if there is enough info to so do
 
Last edited:
Apply Newton's 2nd law to vertical and horizontal force components separately.
 
  • Like
Likes   Reactions: SDTK
Doc Al said:
Apply Newton's 2nd law to vertical and horizontal force components separately.
thank you