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Circular Motion and resultant force

  1. Jan 29, 2016 #1
    1. The problem statement, all variables and given/known data

    WP_20160129_22_51_42_Pro.jpg 2. Relevant equations
    F= mv^2/r
    v = angular vel* r
    3. The attempt at a solution
    resultant force= ma-frictional force
    = mv^2/r - mg*meu
    = (angular vel)^2mx - mg*meu
    But then how do I get the angular speed when I don;2 know the resultant force?
     
  2. jcsd
  3. Jan 29, 2016 #2

    Doc Al

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    Staff: Mentor

    Only one (horizontal) force acts on the mass.
     
  4. Jan 29, 2016 #3
    I don't understand.
     
  5. Jan 29, 2016 #4

    Doc Al

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    Staff: Mentor

    Please identify the forces acting on the mass.
     
  6. Jan 29, 2016 #5
    There is no centripetal force as the mass is not accelerating.
    There is the friction force and centrifugal force
     
  7. Jan 29, 2016 #6

    Doc Al

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    Staff: Mentor

    That would be true if viewed from the rotating frame, which requires the inertial centrifugal force. If so, what is the acceleration?

    Or you can view it from the usual inertial frame, where the only force would be friction and there would be a centripetal acceleration.
     
  8. Jan 29, 2016 #7
    so F=mv^2/r
    mv^2/r=N*meu
    v*angular vel* m = mg*meu
    so angular vel = g*meu/v
    as v= angular vel* x
    angular vel^2=g*meu/x
    so angular vel = (g*meu/x)^(1/2)
    Which is the answer, thank you!
     
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