Circular motion: Car driving along a circular hill

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SUMMARY

A car of mass m traveling along a circular hill of radius r at a constant speed v experiences a net force at the top of the hill described by the equation F = mg - (mv^2)/r. This equation accounts for both gravitational force and the centripetal force required for circular motion. The normal force acting on the car is reduced due to the centripetal acceleration, which is essential for maintaining the car's circular path. Understanding this relationship is crucial for solving problems related to circular motion dynamics.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of centripetal acceleration
  • Familiarity with gravitational force calculations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of centripetal force equations
  • Learn about the effects of varying speed on circular motion
  • Explore real-world applications of circular motion in automotive engineering
  • Investigate the role of friction in circular motion scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators teaching concepts of circular motion and forces in dynamics.

Acid92
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Homework Statement


A car of mass m is traveling along a circular hill of radius r with a constant speed v, write an expression for the force "on the car from the hill" when the car is at the top of the hill

Homework Equations


F (weight) = mg
F (centripetal) = mv^2 /r

The Attempt at a Solution


I think the force on the car from the hill is the normal to the car which at the top of the hill seems to me to be mg. The actual answer is F = mg - (mv^2)/r, I can't seem to figure out how theyve come to this.
 
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Acid92 said:
I think the force on the car from the hill is the normal to the car which at the top of the hill seems to me to be mg. The actual answer is F = mg - (mv^2)/r, I can't seem to figure out how theyve come to this.
The normal force at the top of the hill would equal mg if there were no acceleration. But there is acceleration, so apply Newton's 2nd law to figure out the normal force.
 
Doc Al said:
The normal force at the top of the hill would equal mg if there were no acceleration. But there is acceleration, so apply Newton's 2nd law to figure out the normal force.

Ah right, I forgot that there would be a centripetal acceleration even when the car is at the top of the hill, thanks!

mg - normal = ma = m(v^2 /r)
normal = mg =(mv^2)/r
 

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