Circular Motion (finding speed)

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SUMMARY

The discussion centers on calculating the minimum speed of a ball in circular motion at the top of its path. The ball has a mass of 0.23 kg and is attached to a string with a radius of 0.75 m. The participant utilized the equation F = mv²/R and derived the centripetal force to be 1.7 N, leading to a calculated speed of 2.35 m/s. The expected answer was 2.7 m/s, prompting further analysis of the forces involved, including gravity and tension.

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  • Understanding of circular motion dynamics
  • Familiarity with Newton's laws of motion
  • Knowledge of centripetal force calculations
  • Ability to manipulate algebraic equations
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  • Study the concept of centripetal acceleration in detail
  • Learn about the effects of tension in circular motion
  • Explore the role of gravitational force in vertical circular motion
  • Practice solving problems involving circular motion with varying masses and radii
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Homework Statement


A ball of mass 0.23 kg is attached securely to a string, then whirled at a constant speed in a vertical radius of 0.75 m. Calculate the minimum speed of the ball at the top of the path if it is to follow a complete circle.


Homework Equations


F = mv(squared)/R


The Attempt at a Solution


I first solved for Fc when the ball is at the top of the circle with F=mv(squared)/R - mg and it equals 1.7 N. I then rearranged the equation to solve for V using V = the square root of FR/m and got the answer 2.35 m/s. My sheet says the answer is 2.7, which is pretty close to what I got, but I may have done something wrong. Any thoughts?
 
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This is what i think, right so the forces acting on the mass are gravity and the tension of the string, it's best to draw a diagram.
T = tension.
Defining positive direction to be downwards.At the top of the circle: F = mg + T

As you say F= (mv^2)/r for circular motion. So equate these.

Now can you figure out how to find the minimum speed?
 
Yes, I've figured it out now, thanks!
 

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