Circular Motion Force at Point A: Stunt Car on Frictionless Track

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The discussion focuses on calculating the force exerted by a stunt car on a frictionless track at point A, given the car's mass of 1800 kg and a track radius of 9.9 m. The user attempts to find the car's speed using the formula for centripetal acceleration but expresses confusion about the conditions of the problem, particularly regarding the vertical loop and the car's trajectory. It is clarified that since the track is frictionless, the car cannot accelerate using its engine, and it must maintain a specific speed to stay on the track. The key point is to determine the required speed at the top of the loop and apply conservation laws to find the force at point A. Understanding these concepts is crucial for solving the problem accurately.
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Homework Statement


In the figure, a stunt car driver negotiates the frictionless track shown in such a way that the car is barely on the track at the top of the loop. The radius of the track is 9.9 m and the mass of the car is 1800 kg. Find the force of the car on the track when the car is at point A

http://session.masteringphysics.com/problemAsset/1107086/1/7.10.jpg"

Homework Equations



Accelaration(radius) V2/R F=ma


The Attempt at a Solution



massxacceleration =1800kg x V2/9.9m ... v2=1800kg/9.9 =181 .. v=13.4 m/s

F=1800kg x (13.4)2/9.9

Can someone help me please.. what am I doing wrong?
 
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Is the loop vertical? Is the car traveling on an inclined slope?
 
sorry for the confusion i included a picture link for the problm
 
If the track is frictionless then his trajectory is ballistic; he can't use the engine to accelerate because the tires have no friction with the track.

The condition posed is that the car is "barely on the track at the top of the loop". So work out its required speed there. Then use whatever conservation laws spring to mind.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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