Circular Motion- Just a few quick questions

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Homework Help Overview

The discussion revolves around two problems related to circular motion. The first problem involves a ride at an amusement park where a person experiences a force due to circular motion, and the second problem concerns a car negotiating a circular turn with changing friction conditions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to apply the formula for centripetal force to the first problem but questions their calculation after realizing a mistake in mass. For the second problem, they express uncertainty about how to begin and mention relevant equations without a clear approach.

Discussion Status

Some participants have provided insights into the relationships between forces involved in circular motion, particularly noting that the frictional force must equal the centripetal force for the car on the wet patch. There is an ongoing exploration of how to set up the equations for both scenarios.

Contextual Notes

The original poster has indicated confusion regarding the application of formulas and the information provided in the second problem, particularly the impact of reduced friction on the car's speed.

alex7298
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Homework Statement


The first problem is "at an amusement park there is a ride in which cylinrically shaped chamber spin around a central axis. People si in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.2m/s and an 83kg person feels a 560N force pressing against his back. What is the radius of the chamber?




Second question- "A car is safely negotiating an unbanked circular turn at a speed of 21m/s. The maximum static frictional force actson the tires. Suddenly there is a wet patch in the road reduces the maximum static frictional force by a factor of three. If the car is to continue safely around the curve, to what speed must the driver slow the car?



Homework Equations



For the first problem, i used Fc=mv^2/r
so r=mv^2/Fc...r=(38kg)(3.2m/s^2)/560N=.69, but the answer should be between 1-2. Where am i going wrong?




The Attempt at a Solution



I have no idea where to start for the second question
 
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nvm about the first question. i just realized i put 38kg instead of 83.

now i only need help on the second
 
the only equations that i can think of that are of any relevance are
Uk=Fk/Fn
Fc=mv^2/r
and that's about it...but i don't know where to start because the only thing it gives you is velocity
 
To negotiate the unbanked curve Fk must be equal to Fc. In both the cases Fn remains constant. Wright down two equations for dry road and wet patch and solve for v.
 

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