While learning to drive, you are in a 1 320-kg car moving at 34.0 m/s across a large, vacant, level parking lot. Suddenly you realize you are heading straight toward a brick sidewall of a large supermarket and are in danger of running into it. The pavement can exert a maximum horizontal force of 6 300 N on the car.
(1) Suppose you apply the brakes and do not turn the steering wheel. Find the minimum distance you must be from the wall to avoid a collision.
(2) If you do not brake but instead maintain constant speed and turn the steering wheel, what is the minimum distance you must be from the wall to avoid a collision?
F = ma
a = V^2 / r
The Attempt at a Solution
m = 1320 kg
v = 34 m/s
F = 6300 N
(1) F = ma
6300 N = 1320kg a ---> a = 6300 N/1320kg = 4.77 m/s^2
Vf^2 = Vi^2 x 2ad
0 = (34 m/s)^2 + (2)(4.77)d
(34m/s)^2 / 2(4.77m/s^2) = d ---> d = 121.17m (This answer is correct)
(2) a = v^2 / r...
I'm not sure how to answer this second question and where to start. Any ideas?