Circular motion of a Weightless rod

AI Thread Summary
The discussion focuses on the application of conservation of energy to analyze the motion of a weightless rod and its relationship with a sliding ring. A key point raised is the confusion regarding the rod's position after a certain time, as it should not be horizontal if it is free to rotate. Participants clarify the relationship between the tangential velocity of point B and the velocity of point C, leading to the expression for C's distance from point A in terms of the angle theta. The conversation concludes with one participant expressing understanding and seeking additional practice problems related to the topic. The discussion emphasizes the importance of correctly interpreting the physical system and relationships in dynamics.
PitViper
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Homework Statement
weightless rod AB of length a is free to rotate about a fixed end A. At its other end B, a particle of mass m is attached. B is connected to a ring C of mass m by an inelastic string of length a. The ring C slides smoothly along another fixed horizontal rod passing through A. Initially, points A, B, and C are aligned in a straight line with AC = 2a

The system is released from rest, and at time t, the angle CAB is θ.
Relevant Equations
(d/dt (theta)) ^ 2 = (2g)/a * (sin theta)/(1 + 4sin^2 theta)
I used law of conservation of energy to calculate (d theta/ dt)^2 (from:mgasin theta=1/2m(d theta/dt.a)^2+1/2mu^2(u is the velocity of the C ring at time=t)), but wasnt able to find u(velocity of C).Is there any relationship between the tangential velocity of B(d theta/dt.a) and velocity of C(u) that I'm missing?

0CD96F6B-B84A-4AD1-8291-1630B4B74B71.jpeg
 
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Please post a picture showing the physical system.
 
kuruman said:
Please post a picture showing the physical system.
038C06E6-3A1E-4E77-A7D4-947E4CE2A3A4.jpeg
 
PitViper said:
This is how I think It should look like.
Thank you for the drawing.

What are you asked to find? It is not clear from the statement of the problem.

Also, the drawing shows that the rod "after time = t" is horizontal. The statement of the problem says that the "weightless rod AB of length a is free to rotate about a fixed end A." Both cannot be correct. If the rod is free to rotate, it should be at some angle below the horizontal after some time has elapsed.
 
There are two rods. C slides on a fixed, horizontal rod of unspecified length. Particle B is at the end of a massless rod that is free to rotate in a vertical plane about A. Initially, this rod is horizontal so that the ring C is a distance 2a from A.
 
TSny said:
There are two rods. C slides on a fixed, horizontal rod of unspecified length. Particle B is at the end of a massless rod that is free to rotate in a vertical plane about A. Initially, this rod is horizontal so that the ring C is a distance 2a from A.
Ah, I see it now. Thanks.
 
PitViper said:
Is there any relationship between the tangential velocity of B(d theta/dt.a) and velocity of C(u) that I'm missing?
Let ##x## be the distance of C from A. Can you express ##x## in terms of ##a## and ##\theta##?
 
TSny said:
Let ##x## be the distance of C from A. Can you express ##x## in terms of ##a## and ##\theta##?
2a cos theta?
 
  • #10
TSny said:
There are two rods. C slides on a fixed, horizontal rod of unspecified length. Particle B is at the end of a massless rod that is free to rotate in a vertical plane about A. Initially, this rod is horizontal so that the ring C is a distance 2a from A.
Yeah exactly!
 
  • #11
PitViper said:
2a cos theta?
Yes. Can you use this to get the relationship between the speeds of B and C?
 
  • #12
TSny said:
Yes. Can you use this to get the relationship between the speeds of B and C?
Hmmm I don’t quite get it
 
  • #13
How do you get velocity from position?
 
  • #14
PitViper said:
Hmmm I don’t quite get it
I can calculate the mean velocity of C by dividing displacement of C by t,but I don’t see how that can be ended up in final answer(the formula we have to prove)…
 
  • #15
TSny said:
How do you get velocity from position?
first derivative?
 
  • #16
PitViper said:
first derivative?
Oh my god dude I got it
 
  • #17
PitViper said:
Oh my god dude I got it
Thank you very much
 
  • #18
PitViper said:
Thank you very much
EEF3AFD6-3B5F-4488-B84A-471E49A159C2.jpeg

This is it right?
 
  • #19
Can you please suggest me any problems to practice these type of questions?
 
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