In circular motion along a quarter-circle track, starting at 180 degrees (9 o'clock) and ending at 270 degrees (6 o'clock), the total force acting on an object dropped from the start is directed towards the center of the circle. This centripetal force is constant and does not align with the direction of motion at all angles. As the object moves along the track, the direction of the velocity changes, but the centripetal force remains perpendicular to the velocity vector, ensuring the object follows the circular path without external forces or friction.
PREREQUISITESPhysics students, educators, and anyone interested in the principles of motion and forces in circular trajectories will benefit from this discussion.
devanlevin said:in circular motion, on a track, which is exactly a quarter of a circle, starting at 180 degrees(9 0 clock) and ending at 270(6 o clock) what is the direction of the total force working on an object dropped from the start at 180? no external forces, friction etc... is it always with the direction of motion or does it differ at different angles??