Circular Motion: Plane does a loop

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SUMMARY

The discussion focuses on calculating the minimum radius of a vertical loop for a jet moving at 700 km/hr (194.44 m/s) while ensuring the centripetal acceleration does not exceed 6.0g (58.8 N). The relevant equation used is Fcentripetal = MV²/R. Participants clarify that the goal is to find the radius (R) that satisfies the condition of centripetal acceleration being six times the acceleration due to gravity (9.8 m/s²).

PREREQUISITES
  • Understanding of centripetal force and acceleration
  • Familiarity with the equation Fcentripetal = MV²/R
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to convert units (e.g., km/hr to m/s)
NEXT STEPS
  • Calculate the minimum radius using the formula R = MV²/(6g)
  • Explore the effects of speed on centripetal acceleration
  • Research the implications of exceeding maximum g-forces in aviation
  • Learn about the physics of vertical loops in aerodynamics
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in the dynamics of circular motion in aviation will benefit from this discussion.

thussain93
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Homework Statement


A Jet pilot takes his aircraft in a vertical loop. if the jet is moving at a speed of 700km/hr at the bottom of the loop, determine the minimum radius of the loop if the acceleration at the lowest point doesn't exceed 6.0g's (this means 6.0 x acceleration due to gravity on earth)


Homework Equations


Fcentripital = MV^2/R


The Attempt at a Solution



All i know is that 700km/hr is 194.44m/s
and i also know that the Fg at the bottom would be -58.8N
I'm totally stuck, help me out thanks
 
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Welcome to PF!

Hi thussain93! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

It just means find R such that the centripetal acceleration is 6 times 9.8. :smile:
 

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