Circular motion- radius of the plane's vertical loop

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SUMMARY

The radius of the plane's vertical loop, given an 80-kg pilot and an airspeed of 110 m/s, is calculated to be 1,235 meters. This conclusion is derived from the centripetal force equation, Fc = mV²/R, where the forces acting on the pilot at the top of the loop are balanced (Fc = Fg). The pilot experiences free fall at this point, confirming that the centripetal acceleration equals gravitational acceleration (g).

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Homework Statement



An 80-kg pilot flies a plane in a vertical loop. At the top of the loop, where the plane is completely upside-down for an instant, the pilot hangs freely in the seat and does not push against the seat belt. The airspeed indicator reads the 110 m/s. What is the radius of the plane's vertical loop?

Homework Equations



Fc=Fg
Fc=mV2/R

The Attempt at a Solution



So we know that m= 80kg v=110m/s and we are looking for R.
In order to do this, I simply rearranged the Fc=mV2/R equation and solved for R. And this turned out to give me R=1 235m.

I would like if someone could verify that my work here is done correctly and that the significant figures are being respected. Thank you so much for your time and help :)
 
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That is correct. You could also say that centripetal acceleration = v^2/R = g if there is no force on the pilot due to the seat or his seat belt. The pilot at this instant is effectively in 'free fall'
 

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