Circular Motion Question: Change in Vector Angular Velocity

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e-pie
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Homework Statement
A particle is moving along a circular path of radius $$r$$ with uniform speed $$v$$ Through what angle does its angular velocity change when it completes half of circular path?
Relevant Equations
$$\vec{v}=\vec{\omega}\times \vec{r}$$
Hi i am e-pie's brother and he let me use his account.Since $$\vec{\omega}$$ is always perpendicular to the plane.Shouldn't this be $$0^o$$?
 
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e-pie said:
Problem Statement: A particle is moving along a circular path of radius $$r$$ with uniform speed $$v$$ Through what angle does its angular velocity change when it completes half of circular path?
Relevant Equations: $$\vec{v}=\vec{\omega}\times \vec{r}$$

Hi i am e-pie's brother and he let me use his account.Since $$\vec{\omega}$$ is always perpendicular to the plane.Shouldn't this be $$0^o$$?
Looks right to me.
 
Thanks.I was so confused.
And the change in $$\vec{v}$$ is $$180^o$$ since the direction changes?