The discussion revolves around a problem related to circular motion, specifically focusing on the change in vector angular velocity as a particle moves along a circular path. The context involves understanding the relationship between angular velocity and the direction of velocity in circular motion.
Some participants express confusion regarding the change in direction of velocity and its implications for angular velocity. There is acknowledgment of the relationship between the direction of velocity and the angle of change, but no consensus has been reached on the interpretation of angular velocity in this context.
Participants are discussing the implications of angular velocity being perpendicular to the plane of motion and how this relates to the change in direction of the velocity vector as the particle moves along the circular path.
Looks right to me.e-pie said:Problem Statement: A particle is moving along a circular path of radius $$r$$ with uniform speed $$v$$ Through what angle does its angular velocity change when it completes half of circular path?
Relevant Equations: $$\vec{v}=\vec{\omega}\times \vec{r}$$
Hi i am e-pie's brother and he let me use his account.Since $$\vec{\omega}$$ is always perpendicular to the plane.Shouldn't this be $$0^o$$?
Yes.e-pie said:Thanks.I was so confused.
And the change in $$\vec{v}$$ is $$180^o$$ since the direction changes?