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Circular Motion (standing on a carousel)

  1. Jan 27, 2010 #1
    Hi again,

    I'm sorry for all of the questions in this section. I am having the worst time trying to understand how to set up the problems. I know the equation for acceleration is a= V^2/r; however for this problem I am looking to find the velocity and time. Again, I would appreciate any kind of help possible.

    What are the period and speed of a person on a carousel if the person has an acceleration with a magnitude of 0.7 m/s2 when she is standing 3.8 m from the axis?

    What are her acceleration magnitude and speed if she then moves to a distance of 2.1 m from the carousel center and the carousel keeps rotating with the same period?

    Thank you!
     
  2. jcsd
  3. Jan 27, 2010 #2

    tiny-tim

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    Hi dragonladies1! :smile:

    (try using the X2 tag just above the Reply box :wink:)

    Just apply your v2/r formula (and use v = ωr). :smile:
     
  4. Jan 27, 2010 #3
    Thank you. Using my v2/r formula I came up with 55.63 and I"m not sure what the other formula is. My teacher hasn't mentioned anything using omega.
     
  5. Jan 27, 2010 #4

    tiny-tim

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    oh, it's just the fairly obvious formula that if your radius is r cm, and your angular speed is ω radians per second, then your actual speed (tangential) is ωr cm per second. :smile:

    (and the period is 2π/ω seconds)
     
  6. Jan 27, 2010 #5
    Ok, so I determined that the speed is 1.63, but I dont know why I can't figure out how to find the period for my problem. I plugged in

    Period= 2π/.43=14.65.

    Is this correct?
     
  7. Jan 28, 2010 #6

    tiny-tim

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    Yup! :biggrin:

    (or 14.64)

    (The reason why it's 2π/(angular speed) is because the period T is the time it takes to go 2π: so (angular) speed = (angular) distance over time, so ω = 2π/T. wink:)
     
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