Circular motion , the loop the loop

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NihalRi
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Homework Statement


The loop-the-loop machine has radius R of 18m
(a) What is the minimum speed at which a cart must travel so that it will safety loop the loop
(b) what will the speed at the top be in this case

Homework Equations


Centipetal force = m*v^2/r
Kinetic and potential energies = (1/2) m*v^2 and mgh respectively

The Attempt at a Solution


(a) equating weight and centripetal force and then solving for v I got an answer for velocity of 13.2 but the actual answer is 30
(b) based on (a) calculate the velocity using energy equations
(1/2)m×v^2 = mgh + (1/2) m×v^2
 
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NihalRi said:
(a) equating weight and centripetal force and then solving for v I got an answer for velocity of 13.2 but the actual answer is 30
I believe (a) is asking for the speed at the bottom. (Solve (b) first.)
 
Doc Al said:
I believe (a) is asking for the speed at the bottom. (Solve (b) first.)
I get what it's asking just not how to get the answer