Is Angular Momentum Conserved During the Changing of the String Length?

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SUMMARY

The discussion centers on the conservation of angular momentum when the length of a string attached to a mass is shortened during motion. The object, with a mass of 500 g and an initial velocity of π m/s, moves in a circular orbit of radius R = 50 cm. When the string length is halved to r = R/2, the period of motion is calculated using the formula T = (2πR) / v, yielding a period of 0.5 seconds. However, the correct understanding is that angular momentum remains conserved despite the change in string length, which affects the period but not the speed of the mass.

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AlexanderIV

Homework Statement


An object with mass m is attached to a string with initial length R, and moves on a frictionless table in a circular orbit with center C as shown in the figure. The string is also attached to the center, but its length is adjustable during the motion. The object initially moves with velocity v and angular velocity ω.
Given: m = 500 g, v = π m/s, R = 50 cm
If the length of the string is shortened from R to r = R/2 while the mass is moving, what will be the new period in SI units?

Homework Equations


T = (2πR) / v

The Attempt at a Solution


T = (2πR) / v = (2π0.5) / π = 1
=> T = (2πR/2) / v = 0.5 s

But apparently 0.5 is not the correct answer and I do not understand why.
 
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AlexanderIV said:
T = (2πR) / v = (2π0.5) / π = 1
=> T = (2πR/2) / v = 0.5 s

But apparently 0.5 is not the correct answer and I do not understand why.
Does the speed change when the string is shortened?
 
TSny said:
Does the speed change when the string is shortened?

No, it doesn't.
 
AlexanderIV said:
No, it doesn't.
Can you think of any physical quantity that remains conserved during the changing of the length of the string? (Maybe it's something you have recently covered in your course.)
 

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