Clarification between average velocity and average speed

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Average velocity is calculated by dividing total displacement by total time. Average speed, on the other hand, requires measuring total distance traveled over total time, not just averaging speeds. The formula (v1 + v2) / 2 is applicable when an object moves at speeds v1 and v2 for equal time periods, particularly under constant acceleration. For constant acceleration in a straight line, the average speed and velocity can be found using the average of initial and final speeds. Understanding these distinctions is crucial for accurate calculations in physics.
cmkc109
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To find average velocity, you do total displacement over total time
To find average speed, you add up the speeds / total speeds there are? (Eg. (10+20)/2)

Am I correct?
 
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cmkc109 said:
To find average velocity, you do total displacement over total time

Correct.

To find average speed, you add up the speeds / total speeds there are? (Eg. (10+20)/2)

No, you take the total distance along the path traveled, over the total time. For "total distance", imagine tracing out the path with a string, then straightening the string and measuring its length with a ruler.
 
thanks for your reply! but when do you use v1 + v2 /2 ? or did i remember this wrong?
 
cmkc109 said:
thanks for your reply! but when do you use v1 + v2 /2 ? or did i remember this wrong?

You can use (v1+v2)/2 for the average speed if you first moved with speed v1 and then with speed v2 for the same amount of time. (not for the same amount of distance).

For constant acceleration in a straight line, the average speed (and velocity as well) is \frac {v_i + v_f}{2}. the average of initial and final speed.
 
cmkc109 said:
thanks for your reply! but when do you use v1 + v2 /2 ? or did i remember this wrong?
Hi. I think you forgot some parentheses.

You use that formula when acceleration is constant and you need to find the velocity at a time midway between the time that you measure velocity as v1 and the time you measure velocity as v2.
 
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