Classifying an Alternating Factorial Series

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Homework Statement


Classify the series as absolute convergent, conditionally convergent, or divergent.

[tex] \Sigma^{\infty}_{k = 1} (-1)^{k-1}\frac{k!}{(2k-1)!}[/tex]


Homework Equations


The Alternating Series Test: conditions for convergence
decreasing
lim --> infinity ak = 0


The Attempt at a Solution


I am not sure how to find out if the series is decreasing. Since it is a factorial, I cannot take the first deriative test.

I was wondering if I should use the Alternating Series Test at all, since it is an factorial.

Can someone help me here?
 
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Thanks.

If I try the ratio I got stuck with the factorial.

[tex] \frac{(k+1)!}{(2(k+1)-1)!} * \frac{(2k-1)!}{k!} = \frac{(2k-1)!}{(2(k+1)-1)!} * (k+1)[/tex]


Can I write

[tex](2(k+1)-1)! = (2k+2-1)! = (2k+1)![/tex]
 
dba said:
Thanks.

If I try the ratio I got stuck with the factorial.

[tex] \frac{(k+1)!}{(2(k+1)-1)!} * \frac{(2k-1)!}{k!} = \frac{(2k-1)!}{(2(k+1)-1)!} * (k+1)[/tex]


Can I write

[tex](2(k+1)-1)! = (2k+2-1)! = (2k+1)![/tex]
Yes, of course. And so you have (2k-1)!/(2k+1)!= (2k-1)!/[(2k+1)(2k)(2k-1)!]
 
Oh, ok.
Thank you! I was able to solve this one :smile: