Closed form for (in)finite sums

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SUMMARY

The discussion centers on the closed form of the sum \(\sum_{k=1}^{n}k^p\) and its properties, particularly for values of \(p\) greater than or equal to zero, which are addressed through Faulhaber's formula. For divergent series, the concept of zeta function regularization is introduced, with the limit \(\lim_{n \rightarrow \infty}\sum_{k=1}^{n}k = \frac{-1}{12}\) highlighted. The conversation also explores the significance of these sums, questioning their realism in mathematics, and discusses the existence of closed forms for negative \(p\) values, particularly for even integers. The dimensionality of the sums is emphasized, indicating that a universal formula for varying \(k\) and constant \(p\) is unattainable due to the differing dimensions involved.

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henpen
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I have a set of questions concerning the perennial sum
\large \sum_{k=1}^{n}k^p
and its properties.

1. For p \ge 0, the closed form of this is known (via Faulhaber's formula).
I know little about divergent series, but I've read that in some sense there exists a value associated with these sums as n \rightarrow \infty: for instance \lim_{n \rightarrow \infty}\sum_{k=1}^{n}k = \frac{-1}{12} (here)? I think this is called zeta function regularisation.

a. What is the significance of such sums? Are they useful realistic compatable-with-rest-of-mathematics, or wholly artificial? What evidence is there of these pseudosums' existence?

b. What are they for p \ge -1 (hoping that the Harmonic series, p = -1, has such a 'pseudo-sum')?2. Moving on to p < 0. For even p the limit as n \rightarrow \infty infinity is known (Euler).

a. Is there a Faulhaber equivalent in this case (a closed form of the sum up to n for either even or integer n)?

b. Are the odd p's infinite series likely to be found?For comparison, with constant k and changing p:
\large \sum_{p=1}^{n}k^p= \frac{1-k^{p+1}}{1-k}
I would love if for constant p and changing k was a formula as complete as this.

Thank you for volunteering to suffer my question.
 
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The problem why this can't be is a dimensional one. If we have a constant ##p## and changing ##k## as in ##\sum_{k=1}^n k^p## we basically add different dimensions:
##p=1## is adding lengths
##p=2## is adding areas
##p=3## is adding volumes
etc.
So there cannot be one formula fits all, because the procedure is so different, and with increasing dimension ##p## the additional amount of each term is less and less relevant compared to the partial sum so far.
 

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