Cn coefficient for a Fourier series

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SUMMARY

The discussion focuses on determining the Cn coefficient for a Fourier series, specifically addressing a misprint in the exponent of the equation. The correct exponent should be positive, which allows for the substitution of variables and the application of Euler's formula, e^(ix) + e^(-ix) = 2cos(x). This clarification resolves confusion regarding the transformation from exponential to cosine form in Fourier series calculations.

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sekowe
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Homework Statement



I have an example were they determine the Cn coefficient for a Fourier series:
2dcisrb.png


My problem is i don't follow what happens in the following moment:
25jdr47.png


neither am i sure how the two e^-inwt comes to be cos(nwt) in the last part.

Homework Equations





The Attempt at a Solution



The only solution I can come up with is to reverse the limits what is obvious and then say: t=-a --> -1*t=-1*-a and then change a for -a in the limit and t for -t. However this doesn't work in other similar problems so I don't think think this is right.
 
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welcome to pf!

hi sekowe! welcome to pf! :smile:

there's a misprint :redface:

the first exponent in the third line should be positive

between the second and third lines, they've substituted u = -t, du = -dt, and then renamed u as t again!

and of course the corrected third line let's you use eix + e-ix = (cosx)/2 :wink:
 
A misprint... Yeah that clears up a lot :D

Thank you very much!
 

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