Co-norm of an invertible linear transformation on R^n

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SUMMARY

The discussion centers on the co-norm of an invertible linear transformation T on R^n, defined as m(T) = inf{|T(x)| : |x| = 1}. It is established that if T is invertible with inverse S, then m(T) equals 1/||S||. Participants explore the relationship between the norms of T and S, aiming to prove the equality by analyzing the set of transformed unit vectors.

PREREQUISITES
  • Understanding of linear transformations in R^n
  • Familiarity with norms and co-norms
  • Knowledge of mathematical proofs and inequalities
  • Concept of infimum and supremum in set theory
NEXT STEPS
  • Study the properties of invertible linear transformations in R^n
  • Learn about the definitions and applications of norms and co-norms
  • Investigate the relationship between the norms of a linear transformation and its inverse
  • Explore techniques for proving inequalities and equalities in mathematical analysis
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Mathematicians, students studying linear algebra, and anyone interested in the properties of linear transformations and their norms.

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Homework Statement


|\;| is a norm on \mathbb{R}^n.
Define the co-norm of the linear transformation T : \mathbb{R}^n\rightarrow\mathbb{R}^n to be
m(T)=inf\left \{ |T(x)| \;\;\;\; s.t.\;|x|=1 \right \}
Prove that if T is invertible with inverse S then m(T)=\frac{1}{||S||}.


Homework Equations


n/a


The Attempt at a Solution


I think probably we need to do something with the norm, but I still can't get it... So thank you.
 
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Equalities of the form inf X = A are often proved by showing that the two inequalities inf X ≤ A and inf X ≥ A both hold. Together they imply equality of course. One of these proofs will typically use that inf X a lower bound of X (consider an arbitrary member of X), and the other will typically use that inf is the greatest lower bound of the set.

How is ##\|S\|## defined? Can you prove anything about the relationship between ##\|S\|## and ##\|T\|##?

Edit: I have so far only proved the inequality ##m(T)\leq 1/\|S\|##. The idea that I think looks the most promising for a proof of the equality is to take a closer look at the set ##\{|Tx|:|x|=1\}##. What is its infimum? What is its supremum?
 
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