How Do You Calculate Current Density Between Coaxial Cylinders?

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Homework Help Overview

The problem involves calculating the current density J(r) between two long, coaxial metal cylinders separated by a dielectric material with given conductivity and dielectric constant. The inner cylinder is held at a potential with respect to the outer cylinder, and the task is to express the current density as a function of the radius between the cylinders.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different attempts to derive the expression for current density, including methods based on resistance and capacitance. Questions arise regarding the correctness of the approaches and the role of the dielectric constant in the calculations.

Discussion Status

Several participants have offered different expressions for J(r) and are evaluating the validity of these approaches. There is an ongoing exploration of the implications of the current being constant across varying radii and the relationship between current density and area.

Contextual Notes

Participants are considering the effects of the dielectric material and questioning the assumptions regarding current flow and charge distribution. The discussion reflects a mix of interpretations and attempts to reconcile different methods without reaching a consensus.

RyanP
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Homework Statement


[/B]
Two long, coaxial metal cylinders are separated by a material of conductivity sigma and dielectric constant epsilon. The radius of the inner cylinder is a, the radius of outer cylinder is b, and the length of both is L.

Suppose that the inner conductor is held at a potential Vo with respect to the outer one. What is the current density J(r) between the two?

Homework Equations


J(r) = I/A = sigma*E
C=Q/V
R=s/(A*sigma)

The Attempt at a Solution


First attempt:
I found resistance of the dielectric to be ln(b/a)/(2pi*L*sigma). As a function of radius r, R(r) = ln(r/a)/(2pi*L*sigma).

Current = V/R = Vo / (ln(b/a)/(2piLsigma)) = Vo*2pi*L*sigma / ln(r/a) as a function of r.
Then divide by Area=2pi*L*r to get current density J(r) = Vo*sigma / (r*ln(r/a)). Second attempt:
Vo = Q/C. I found capacitance of the configuration to be 2pi*epsilon_o*L*epsilon / ln(b/a) using the expression for resistance. Then Q = Vo*2pi*L*epsilon*epsilon_o / ln(b/a).
EA = Q/epsilon_o, so E = Vo*epsilon / (r*ln(b/a)). Using J(r) = E*sigma, I get J(r) = sigma*Vo*epsilon / rln(b/a).

The difference in the two is the presence of epsilon (dielectric constant) in the numerator, and b rather than r in the ln term of the denominator. Are either of these approaches correct?
 
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Can bound charges support current flow?
Better stick with method 1.
 
RyanP said:
Current = V/R = Vo / (ln(b/a)/(2piLsigma))
Looks reasonable (but I've not checked it in detail).
RyanP said:
= Vo*2pi*L*sigma / ln(r/a) as a function of r.
That I don't understand. The same total current has to flow through any given radius, no?
 
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
 
RyanP said:
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
Sounds right, looks right ... I'm buying!
 
RyanP said:
Ok, maybe instead I'll do J(r) = current (constant) / area (function of r). In this case I just get J(r) = V*sigma/(r*ln(b/a)). Does this sound right?
Looks right to me too.
 

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