MHB Coefficent in a infinite power series

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SUMMARY

The coefficient of \(x^9\) in the given infinite power series is definitively 10. This conclusion is drawn from the combinatorial analysis of the equation \(9 = 0 + 9, 1 + 8, 2 + 7, 3 + 6, 4 + 5, 5 + 4, 6 + 3, 7 + 2, 8 + 1, 9 + 0\), which identifies 10 distinct combinations that yield the term \(x^9\). Each combination represents a unique way to sum to 9 using non-negative integers, confirming the coefficient's value.

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How do I find a coefficient of x^9 in a power series like this:
Screenshot 2021-06-03 174217.png
 
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For (a) 9= 0+ 9= 1+8= 2+ 7= 3+ 6= 4+ 5= 5+ 4= 6+ 3= 7+ 2= 8+ 1= 9+ 0.
There are 10 products that give $x^9$ so the coefficient is 10.
 
If there are an infinite number of natural numbers, and an infinite number of fractions in between any two natural numbers, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and... then that must mean that there are not only infinite infinities, but an infinite number of those infinities. and an infinite number of those...

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