- #1
Luis2101
- 13
- 0
A grindstone in the shape of a solid disk with diameter 0.510 and a mass of m= 50.0kg is rotating at w = 900rev/min. You press an ax against the rim with a normal force of N= 160N, and the grindstone comes to rest in 7.00sec.
Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.
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Simply put, I have no idea how to connect the information here to Coefficient of friction.
I have found Torque using t = I*(Angular Acceleration)
Where Moment of Inertia = 1/2 MR^2 = 1.63kg*m^2
And Angular Acceleration was found using w = w(initial) + angular acceleration*t.
I found the angular acceleration to be -2.14 rev/sec^2 (I converted the angular velocity to rev/sec in finding this).
And torque was equal to -3.5N...
I have all this info so far, but have no idea how to connect it to Coefficient of Friction, I thought maybe there would be some ratio with the Normal Force, but I don't have Friction Force so I'm pretty much stuck...
Any help would be greatly appreciated.
-L.
Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.
----
Simply put, I have no idea how to connect the information here to Coefficient of friction.
I have found Torque using t = I*(Angular Acceleration)
Where Moment of Inertia = 1/2 MR^2 = 1.63kg*m^2
And Angular Acceleration was found using w = w(initial) + angular acceleration*t.
I found the angular acceleration to be -2.14 rev/sec^2 (I converted the angular velocity to rev/sec in finding this).
And torque was equal to -3.5N...
I have all this info so far, but have no idea how to connect it to Coefficient of Friction, I thought maybe there would be some ratio with the Normal Force, but I don't have Friction Force so I'm pretty much stuck...
Any help would be greatly appreciated.
-L.