Undergrad Coefficients in a quotient of sums

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The discussion focuses on finding the coefficient of the order \(x^j\) term in the quotient of two infinite power series. Participants suggest using polynomial long division as a method to derive the desired coefficient. An example from a provided resource illustrates this approach effectively. Although the process can be tedious, it is deemed successful for the user's needs. The conversation confirms that there is a systematic way to express the coefficient in question.
Sturk200
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Is there a general way to express, for instance, the coefficient of the order $x^j$ term in the expression

$$\frac{\Sigma_{n}^{\infty}a_nx^n}{\Sigma_{m}^{\infty}b_mx^m}$$ ?

Basically I am working with a quotient of two infinite power series and I want to know the term in this quotient that is proportional to a particular power of the expansion variable. Am I even guaranteed that there will be such a term? How do I find it?
 
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Sturk200 said:
Is there a general way to express, for instance, the coefficient of the order $x^j$ term in the expression

$$\frac{\Sigma_{n}^{\infty}a_nx^n}{\Sigma_{m}^{\infty}b_mx^m}$$ ?

You could try doing division, similar to the way that one divides one polynomial by another polynomial. There's an example on page 3 of http://www2.fiu.edu/~aladrog/IntrodPowerSeries.pdf
 
Stephen Tashi said:
You could try doing division, similar to the way that one divides one polynomial by another polynomial. There's an example on page 3 of http://www2.fiu.edu/~aladrog/IntrodPowerSeries.pdf

That was a bit tedious, but I think it actually worked for my purpose. Thanks!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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