Collision and Kinetic Energy Problem

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SUMMARY

The discussion focuses on an inelastic collision problem involving two balls with masses of 2.50 kg and 1.20 kg, moving at specified velocities and angles. The final velocity of the combined mass after the collision is calculated using conservation of momentum principles. Additionally, the kinetic energy lost during the collision is determined using the formula (1/2)mv^2 = (1/2)mv^2 - Wnc, where Wnc represents non-conservative work. A correction was noted regarding the calculation of the y-component, emphasizing the importance of clearly stating angles in terms of cardinal directions.

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njuice8
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A ball, which has a mass of m1 = 2.50 kg., is moving with a velocity of 8.00 m/s at an angle of 25.0˚ South of West. It collides with a second ball, which has a mass of m1 = 1.20 kg., which is moving with a velocity of 4.75 m/s at an angle of 61.0˚ North of West. They stick together and move as one.
What will be the final velocity v3 of the balls after the collision?
How much kinetic energy was lost in this inelastic collision?

I attached a picture of my work
I'm not sure if my work is right.

Also, for the kinetic part, would I just use (1/2)mv^2 = (1/2)mv^2 - Wnc?

Thanks!
 

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Overall, looks good. But I think you dropped out the factor of 3.7 during the calculation of the y-component which has thrown off your answer for the angle. Also, it's a good idea to state your angle clearly in terms of "south of east" or whatever.
 
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