A simple pendulum consists of a 1.50 kg mass connected to a cord without any mass or friction. Initially the pendulum is vertically positioned when a 2.00 kg mass collides with it, causing the pendulum to displace vertically upward 1.25 m. After the collision, the 2.00 kg mass travels along the frictionless horizontal surface, until it meets a 30 degree incline with a coefficient of kinetic friction of .400. If the mass travels a maximum distance of 1.125 m up the incline, determine the initial velocity that the 2.00 kg mass strikes the pendulum with.
Po=Pf Original Momentum = to Final Momentum
M1V1o+M2V2o=M1V1f+M2V2f Conservation of Linear Momentum
MGYf+MGYo+1/2MVf^2-1/2MVo^2=The coefficient of friction times Nd
Sorry for the poor organization, All lower case letters are meant to be subscript except for the "h" in "U=MGh" and the "d" at the end of the last two equations.
The Attempt at a Solution
I've been working on this for a few days, I think I may have come up with something. I believe the final velocity of the pendulum when it reaches 1.25m height is 4.95 m/s. Also, I'm having difficulty dealing with the 30 degree incline and how that affects the velocity of the 2.00kg mass. I got a velocity of 2.57 m/s when the mass reaches the base of the incline but am not sure where to go from there.
Edit: I think I may have gotten an answer. I used the conservation of linear momentum equation with the velocity of the pendulum and the velocity of the mass at the base of the incline. I got the initial velocity of the 2.00kg mass to be 6.28 m/s. If anyone can confirm this or tell me where I went wrong I would really appreciate it.