Collision in 2 dimensions (Momentum)

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MattsVai
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Homework Statement


Two spacecraft s have linked in space and are coasting with their engines off, heading directly towards Mars. The spacecraft s are thrust apart by large springs. Spacecraft 1 with mass of 1.9 x 10^4 kg, then has a velocity of 3.5 x 10^3 km/h at 5.1 degrees to its original direction. Spacecraft 2 with mass 1.7 x 10^4 kg, has then a velocity of 3.4 x 10^3 km/h at 5.9 degrees to its original direction. Determine the original speed of the two craft when they were linked together.
2. The attempt at a solution
Please see attached my attempt to solve this question. Am I on the right path? Do I have to calculate for Y axis too? Many thanks
 
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  • Handwritten working on lined paper: a momentum conservation equation in the x direction, m1vx + m2vx = m1v1' + m2v2', with the given masses and velocities and the result vx = 3.4 x 10^3 m/s.
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Last edited:
Update:

So Basically, I know now that the force of the spring is in fact internal. But, if there is no velocity on the y-axis why would I have to calculate it? And I on the right path performing calculations for the x-axis only?

Cheers
 
You are indeed. The work done by the spring only acts in a Y direction so because of that, there is no change in speed in the x direction.
 
From looking at your work, you forgot to convert the speeds from Km/h into m/s before plugging the numbers into the equation.