Collision question using conservation of kinetic energy

In summary: There is no such thing as a perfectly elastic collision. A collision is always in some sense inelastic. But in this case, because the two masses are so large and they are moving so fast, the collision is impossible to be perfectly inelastic.
  • #1
tippetmaster
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Homework Statement



A 2.00 kg mas (A) moving at 2.00 m/s strikes another 2.00 kg mass(B) which is at rest. Both are confined to a a straight line to move along.

An impossible outcome for this collision is that A sticks to B and they both move off together at 1.414 m/s. First show that this collision would satify conservation of kinetic energy and then explainwhy this is impossible.

Homework Equations


.5(mA)(vAi)2+.5(mb)(vbi)2=.5(mA)(vAf)2+.5(mb)(vbf)2


The Attempt at a Solution


I get that this is a perfectly ineleastic collision but why is it impossible and what does the question mean by "show that this satifies the consevation of kinetic energy" Does the above question even relate to the equation for the consevation of kinetic energy?

ANy help is appreciated thanks!
 
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  • #2
It's asking you to show that if they both stick together and move off at 1.414ms-1 then kinetic energy is conserved.
 
  • #3
okay what does it mean if kinetc energy is conserved?
 
  • #4
Satisfying conservation of kinetic energy means that the total kinetic energy before the collision is more than or equal the total kinetic energy after the collision since no energy can be created and energy could be lost to other forms, such as sounds, heat etc.

I get that this is a perfectly ineleastic collision
What makes you assume this?
 
  • #5
Because if the colliding objects stick together after the collision then the collision is perfectly inelastic
 
  • #6
so why is this situation impossible?
 
  • #7
Oh sorry misread the question. Yes this impossible scenario is inelastic.

Simply use the conservation of momentum equation to show this is impossible ~

[tex]M_aU_a+M_bU_b=M_aV_a+M_bV_b[/tex] where m=mass, u=intial velocity, v=final velocity.
 
  • #8
Mentallic said:
Oh sorry misread the question. Yes this impossible scenario is inelastic.

Simply use the conservation of momentum equation to show this is impossible ~

[tex]M_aU_a+M_bU_b=M_aV_a+M_bV_b[/tex] where m=mass, u=intial velocity, v=final velocity.

The question is not asking to prove that it's impossible, it's asking to explain why it's impossible.

Is there such thing as a perfectly elastic collision? Why/why not?
 

1. What is the conservation of kinetic energy?

The conservation of kinetic energy is a fundamental law of physics that states that the total amount of kinetic energy in a closed system remains constant over time. This means that the total kinetic energy before a collision is equal to the total kinetic energy after the collision.

2. How is the conservation of kinetic energy applied to collision questions?

In collision questions, the conservation of kinetic energy is used to determine the velocities of objects before and after a collision. By setting the initial kinetic energy equal to the final kinetic energy, we can solve for the unknown velocities using algebraic equations.

3. What is an elastic collision?

An elastic collision is a type of collision where kinetic energy is conserved, meaning that the total kinetic energy before the collision is equal to the total kinetic energy after the collision. In an elastic collision, the objects involved bounce off each other without any loss of energy.

4. What is an inelastic collision?

An inelastic collision is a type of collision where kinetic energy is not conserved, meaning that the total kinetic energy before the collision is not equal to the total kinetic energy after the collision. In an inelastic collision, some of the kinetic energy is converted into other forms of energy, such as heat or sound.

5. What are some real-life examples of collisions where the conservation of kinetic energy is applied?

Some examples of collisions where the conservation of kinetic energy is applied include car crashes, billiard balls colliding, and objects falling to the ground. In each of these cases, the total kinetic energy before the collision is equal to the total kinetic energy after the collision, assuming no external forces are acting on the system.

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