Mathematica Coloring and legending issue

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The plot's color bar does not accurately reflect the colors in the plot, as the color bar displays a single color for a specific value, while the corresponding plot color differs. Additionally, an unexpected blue horizontal line appears on one side of the center, which should not be present. The issue arises because the color scale is based on the temperature function T, but the plotted values correspond to rs, which exceed the temperature range. Specifically, at rh = 0.6, the value of rs is approximately 0.6, while T[0.6] is about 0.53. Clarification and adjustments to the color mapping and plot parameters are needed to resolve these discrepancies.
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Look at the following Image.
The results are okay but clearly the plot colors does not match with the color bar. for example the color bar is showing only single color. the value 0.4 in color bar corresponds to the radius 0.8 which is different color in the plot.

Another issue is that I don't know why that blue horizontal line is there at one side of the center. That should not be there.

I am using the following code-

f[r_] := 1 - (2*M)/r + Q^2/r^2 + (8/3)*Pi*P*r^2
mass = (3*Q^2 + 3*r^2 + 8*P*Pi*r^4)/(6*r) /. r -> rh;
T[r_] := (-Q^2 + r^2 + 8*P*Pi*r^4)/(4*Pi*r^3)
veff[r_] := f[r]/r^2
rp = r /. Last[NSolve[D[veff[r], r] == 0, r, Reals]] /. M -> mass

rs = rp/Sqrt[f[rp]] /. M -> 0.9;
Q = 0.1;
P = 0.3315;

plot = ParametricPlot[{rs*Cos[\[Theta]], rs*Sin[\[Theta]]}, {rh, 0.37, 0.6}, {\[Theta],
0, 2*Pi}, Axes -> False, ColorFunctionScaling -> False,
ColorFunction -> Function[{x, y, rh}, ColorData["SunsetColors"][Rescale[T[rh],
{T[0.37],T[0.6]}]]],
PlotLegends -> BarLegend[{"SunsetColors", {T[0.37], T[0.6]}}, LegendLabel ->
Style[HoldForm[T], 14]]]



Can anyone help me? Thanks in advance.
plot.png
 
Last edited:
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Your color scale is based on T, but what you are plotting is rs. For rh in the range of the parametric plot, the values of rs go beyond the corresponding range in T, for example at rh = 0.6, rs ≈ 0.6, while the color scale goes tp to T[0.6] ≈ 0.53.
 

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