Physics, find the time it takes.

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SUMMARY

The discussion focuses on calculating the time it takes for an object to reach the ground using the kinematic equation Δy = Voy * t + (1/2)ay * t². The user attempts to solve for time (t) using initial velocity (Voy) of -5 m/s and acceleration due to gravity (ay) of -9.81 m/s² over a height of -100 m. The correct interpretation of the quadratic formula yields two potential solutions for t, where only the positive value is physically meaningful. The discussion emphasizes the importance of selecting the appropriate solution based on the context of the problem.

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Homework Statement


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How long does it take to reach the ground? And what is the angle of impact with the ground?

Homework Equations





The Attempt at a Solution


Δy = Voy * t + (1/2)ay * t2
t = (-5 m/s) ± √(5 m/s)2 - 4(1/2)(-9.81 m/s2)(-100m) / 2(1/2)(-9.81 m/s2)

t = -5 m/s ± (4.54)

Is it suppose to be 4.54 or -4.54? And am I suppose to add or subtract the two variables to find t??
 
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Sometimes you will get two possible solutions, you ignore the one that is not physical or does not correspond to your situation.
In this case, your math is for an inverted parabola - this will intersect the "ground level" in two places - one to the left of the start, and one to the right. Part of the exercize is to get you to pick the one that corresponds to your problem.

Hopefully in your actual work you will have more explanatory bits.
eg. from your numbers, it looks like b^2-4ac < 0 and the division by -9.8 should make the first term in t positive.
 

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