MHB Comaximal Ideals in a Principal Ideal Domain

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In a principal ideal domain (PID), two ideals (a) and (b) are comaximal if their sum equals the entire ring, meaning A + B = R. This is equivalent to the existence of a greatest common divisor for a and b, indicating that they are coprime or relatively prime. If a and b are relatively prime, there exist elements m1 and m2 such that 1 can be expressed as a linear combination of a and b. Consequently, the ideal generated by a and b contains 1, confirming that it is equal to R. Thus, the relationship between comaximal ideals and greatest common divisors is established in PIDs.
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Prove that in a prinicpal ideal domain, two ideals (a) and (b) are comaximal if and only if a greatest common divisor of a and b (in which case (a) and (b) are said to be coprine or realtively prime)

Note: (1) Two ideals A and B of the ring R are said to be comaximal if A + B = R

(2) Let I and J be two ideals of R
The sum of I and J is defined as I+J = \{ a+b | a \in I, b \in J \}
 
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Re: Comaximal Ideas in a Principal Ideal Domain

I think you've found the answer on MHF.
 
Re: Comaximal Ideas in a Principal Ideal Domain

Well ... I am still working on the problem ... but I will be using your guidance regarding the way to progress

At my day job at the moment ... but will use your hint when I return to the problem

Thanks again

Peter
 
by def, two elements a,b in a PID are relatively prime if there exist, $m_1,m_2 \in $, such
that 1 = $m_1a+m_2b$

now if $a,b$ are relatively prime then

$\{r_1a + r_2b | r_1,r_2 \in R\}$, contains 1, if an ideal contains 1, then that ideal is identical to R.

Now <a> + <b> = $\{g_1a + g_2b | g_1,g_2 \in R\}$
 
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