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Combinatorial Number Theory Problem

  1. Apr 25, 2012 #1
    Hello,

    I would like to see a solution to the following problem:

    Let A be a finite collection of natural numbers. Consider the set of the pairwise sums of each of the numbers in A, which I will denote by S(A). For example, if A={2,3,4}, then S(A)={5,6,7}. Prove that if S(A)=S(B) for two different finite sets of natural numbers A and B, then |A|=|B|, and |A|=|B| is a power of 2.

    I find this problem interesting, but I am working on other problems. Anyone have ideas?

    Thanks,
    Mathguy
     
  2. jcsd
  3. Apr 25, 2012 #2

    mathman

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    You haven't defined |A| for this situation.
     
  4. Apr 25, 2012 #3
    For a set C, |C|=the cardinality of C.
     
  5. Apr 25, 2012 #4


    Well, if one considers zero a natural number (many do) then both claims above are false, as [itex]\{2,3,4\},\{0,2,3,4\}[/itex] , otherwise...perhaps by induction on [itex]|A|+|B|[/itex] ...

    DonAntonio
     
  6. Apr 26, 2012 #5
    Maybe I'm missing something, but it looks like for A = {1,2,3,4,5,6,7} and B = {1,2,3,5,6,7}

    S(A) = {3,4, ... 12,13} = S(B), but |A|=7 and |B|=6

    Maybe there should be some other restrictions on A and B?

    (guessing) If neither A nor B may be a subset of the other, then consider {1,2,3,4,6,7,8,9}, {1,2,3,5,7,8,9} . Cardinalities 8 and 7.
     
  7. Apr 27, 2012 #6
    Great Scott, you may be right catellus!
     
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