Combinatorics - In how many ways can three aces and two kings be drawn

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The discussion focuses on calculating the number of ways to draw three aces and two kings from a standard deck of cards. It establishes that there are 288 ways to draw the cards in a specific order, such as "AAAKK". However, to find the total combinations regardless of order, one must multiply 288 by the number of unique arrangements of the cards. The correct formula for this is 5!/(3!2!), resulting in 10 unique arrangements. Thus, the total number of ways to draw three aces and two kings is 288 x 10 = 2880.

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1. In how many ways can three aces and two kings be drawn?

2. There are 24 ways three aces can be drawn and there are 12 ways two kings can be drawn.
3. I tried 24x12=288 ways to get three aces and two kings.. people are telling me that it is wrong, but I am not understanding why
 
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YODA0311 said:
1. In how many ways can three aces and two kings be drawn?

2. There are 24 ways three aces can be drawn and there are 12 ways two kings can be drawn.
3. I tried 24x12=288 ways to get three aces and two kings.. people are telling me that it is wrong, but I am not understanding why
First look at specifically "AAAKK" in that order. There are 4 aces so 4 ways to draw that first ace. After that, there are 3 aces left so 3 ways to get the second ace. After drawing the second ace, there are 2 aces left so 2 ways to draw that third ace. There are 4 kings so 4 ways to draw the first king. Then there are 3 kings left so 3 ways to draw that second king.

So far that says there are 4(3)(2)(4)(3)= 24(12)= 288 ways to get "AAAKK" in that specific order. But the same kind of analysis would show that there are 288 ways to get, say, "AKAKA" or three aces and two kings in any specific order. You need to multiply 288 by the number of ways to order 3 "A"s and 2 "K"s. Do you know how to find that?
 


HallsofIvy said:
First look at specifically "AAAKK" in that order. There are 4 aces so 4 ways to draw that first ace. After that, there are 3 aces left so 3 ways to get the second ace. After drawing the second ace, there are 2 aces left so 2 ways to draw that third ace. There are 4 kings so 4 ways to draw the first king. Then there are 3 kings left so 3 ways to draw that second king.

So far that says there are 4(3)(2)(4)(3)= 24(12)= 288 ways to get "AAAKK" in that specific order. But the same kind of analysis would show that there are 288 ways to get, say, "AKAKA" or three aces and two kings in any specific order. You need to multiply 288 by the number of ways to order 3 "A"s and 2 "K"s. Do you know how to find that?

Wow I would like to say thank you, because you actually explained it in a manner I can understand.
On your question, "the number of ways to order 3 "A"s and 2 "K"s. Do you know how to find that?" I would use, n!/(n-r)!= 5!/(5-3)!=5!/2!=60 ways to order 3 "A" cards out of 5 cards.
Then n!/(n-r)!=5!/(5-2)!=5!/3!=20 ways to order 2 "k" cards out of 5 cards.
Then should I add 20 +60= 80 total ways to order 3"A"s and 2"k"s?
 

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