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In how many ways can three aces be drawn?

  • Thread starter YODA0311
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  • #1
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probability help plzzz

1. In how many ways can three aces be drawn?



2. I used this formula - P= n!/(n-r)!
n r


3. Here is my attempt- 52!/(52-3)!=52!/49!= 132600, but that is off to me.

I googled this problem and the person got "There are 4*3*2 = 24 sequences in which 3 aces can be drawn from a deck containing 4 aces." However I do not know how they reached their conclusion :(

Homework Statement





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The Attempt at a Solution

 

Answers and Replies

  • #2
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well i think i got it, however i would like to know if it is correct
n!/(n-r)!=4!/(4-3)!=4!/1=24/1=24 possible ways to draw three aces
 
  • #3
Dick
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well i think i got it, however i would like to know if it is correct
n!/(n-r)!=4!/(4-3)!=4!/1=24/1=24 possible ways to draw three aces
That's right if you are considering order, i.e. you consider clubs-diamonds-spades to be different from clubs-spades-diamonds.
 
  • #4
Redbelly98
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However, I will add that in card-drawing problems, one typically does not consider the order to be important. I.e., clubs-diamonds-spades and clubs-spades-diamonds are considered to be the same.

While there is a formula that gives the right answer, the answer to this one can easily be found (or checked) using common sense.

Moderator's note: thread moved from Intro Physics to Precalc Math.
 

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