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**probability help plzzz**

**1. In how many ways can three aces be drawn?**

**2. I used this formula - P= n!/(n-r)!**

n r

n r

**3. Here is my attempt- 52!/(52-3)!=52!/49!= 132600, but that is off to me.**

I googled this problem and the person got "There are 4*3*2 = 24 sequences in which 3 aces can be drawn from a deck containing 4 aces." However I do not know how they reached their conclusion :(

I googled this problem and the person got "There are 4*3*2 = 24 sequences in which 3 aces can be drawn from a deck containing 4 aces." However I do not know how they reached their conclusion :(