- #1

Mana Knight

- 1

- 0

## Homework Statement

A converging lens and a diverging lens, separated by a distance of

**30 cm**, are used in combination. The converging lens has a focal length of

**15 cm**. The diverging lens is of unknown focal length. An object is placed

**19 cm**in front of the converging lens; the final image is virtual and is formed

**12 cm**before the diverging lens. What is the focal length of the diverging lens?

## Homework Equations

I know for sure I'm suppose to use the equations:

1/f1 = 1/p1 + 1/q1

1/f2 = 1/p2 + 1/q2

p2 = s - q1

## The Attempt at a Solution

Here's what I tried to do. I understand that I'm suppose to do one lens at a time:

1/q1 = 1/f1 - 1/p1 = 1/15cm - 1/19cm = 71.25cm

p2 = s - q1 = 30cm - 71.25cm = -41.25cm

f2 = 1/q2 + 1/p2 = 16.923cm

I tried changing signs of each number part, but I'm still not getting the right answer. I tried reading class notes and textbook and I still can't figure out what I did wrong, or if there's something I'm missing

There's another similar problem to this I'm having difficulty with (which adds height), but I think I'll understand that too once I get this.

Any help would be greatly appreciated. :)