- #1
Kaelor
- 1
- 0
- Homework Statement
- Finding the distance between the back surface of the first lens and the front surface of the back lens.
- Relevant Equations
- 1/f = 1/s_o + 1/s_i
Homework Statement:: Finding the distance between the back surface of the first lens and the front surface of the back lens.
Homework Equations:: 1/f = 1/s_o + 1/s_i
I have two positive thin lenses that are separated by a distance of 5 cm. The focal lengths of the lenses are F_1 = 10 cm and F_2 = 20 cm. I placed an object 2 cm to the left of the front focal point and calculated the image by using the equation 1/f = 1/s_o + 1/s_i twice, so that the image of the first lens became the object of the second lens.
See the attached images for an illustration of the thin lens system.
(credit to www.livephysics.com)
I am then told to insert two thick bi-convex lenses of 10 cm and 20 cm effective focal lengths into the system instead of the thin optical lenses, so that I get the same image with the same object 2 cm to the left of the front focal point. These thick lenses have all of the typical information available that one would find in a lens catalogue (radius of curvature, principal plane distances, refractive index, etc.), and I can provide this information if requested.
See the attached images for an illustration of the thick lens system.
(Note that d in this thick lens picture is different to the distance that I am describing below.)
(From Optics, Fifth Edition, by Hecht.)
I'm now trying to find the distance between the back surface of the first lens and the front surface of the back lens.
I have two problems:
1. I'm not sure that I'm correctly interpreting what is meant by inserting the thick lenses, so that one gets the same image with the same object 2 cm to the left of the front focal point.
2. Despite a tremendous amount of research, I don't understand how it is possible to infer the the distance between the two thick lenses that were inserted instead of the thin lenses. I wondered if I was just misunderstanding what is exactly meant by "inserting" thick lenses instead of thin lenses in a system, but I have looked through a lot of optics resources and found nothing that indicates that the lenses must be "inserted" in a specific way that allows for deduction of the distance. I am told that the distance is somewhere between 4 - 5 cm, but I don't understand how such a thing can be calculated. Since this value is so close to the original thin lens distance of 5 cm, this leads me to believe that I am completely misunderstanding something about the nature of thick lens systems and how they are "inserted" into a thin lens system. Could it be that, to "insert" a thick lens instead of a thin lens means to align the secondary principal plane of the first thick lens with the first thin lens, and align the primary principal plane of the second thick lens with the second thin lens, so that the distance between the secondary principal plane of the first lens and the primary principal plane of the second lens is 5 cm?
I would greatly appreciate it if people could please take the time to clarify this.
Homework Equations:: 1/f = 1/s_o + 1/s_i
I have two positive thin lenses that are separated by a distance of 5 cm. The focal lengths of the lenses are F_1 = 10 cm and F_2 = 20 cm. I placed an object 2 cm to the left of the front focal point and calculated the image by using the equation 1/f = 1/s_o + 1/s_i twice, so that the image of the first lens became the object of the second lens.
See the attached images for an illustration of the thin lens system.
(credit to www.livephysics.com)
I am then told to insert two thick bi-convex lenses of 10 cm and 20 cm effective focal lengths into the system instead of the thin optical lenses, so that I get the same image with the same object 2 cm to the left of the front focal point. These thick lenses have all of the typical information available that one would find in a lens catalogue (radius of curvature, principal plane distances, refractive index, etc.), and I can provide this information if requested.
See the attached images for an illustration of the thick lens system.
(Note that d in this thick lens picture is different to the distance that I am describing below.)
(From Optics, Fifth Edition, by Hecht.)
I'm now trying to find the distance between the back surface of the first lens and the front surface of the back lens.
I have two problems:
1. I'm not sure that I'm correctly interpreting what is meant by inserting the thick lenses, so that one gets the same image with the same object 2 cm to the left of the front focal point.
2. Despite a tremendous amount of research, I don't understand how it is possible to infer the the distance between the two thick lenses that were inserted instead of the thin lenses. I wondered if I was just misunderstanding what is exactly meant by "inserting" thick lenses instead of thin lenses in a system, but I have looked through a lot of optics resources and found nothing that indicates that the lenses must be "inserted" in a specific way that allows for deduction of the distance. I am told that the distance is somewhere between 4 - 5 cm, but I don't understand how such a thing can be calculated. Since this value is so close to the original thin lens distance of 5 cm, this leads me to believe that I am completely misunderstanding something about the nature of thick lens systems and how they are "inserted" into a thin lens system. Could it be that, to "insert" a thick lens instead of a thin lens means to align the secondary principal plane of the first thick lens with the first thin lens, and align the primary principal plane of the second thick lens with the second thin lens, so that the distance between the secondary principal plane of the first lens and the primary principal plane of the second lens is 5 cm?
I would greatly appreciate it if people could please take the time to clarify this.